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Vector Space (Theorem-5)

Statement:- The necessary & sufficient conditions for a non-empty subset W of a vector spaceV(F) to be a subspace of V are

( 1)  αW, βW α-βW
(2)  aF, αW aαW

Proof:-                Necessary Condition:-

Let V be a vector space over the field F and W be its subspace.
  W will be a vector space over the same field F.

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Field & Integral Domain

          Integral domain:-

1- A commutative ring with unity element and without zero divisors is called an integral domain.
2- An algebraic system (D,+,.) where D is a non-empty set with two binary compositions to be denoted by addition and multiplication is called an integral domain if following axioms are satisfied-

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Definition of Ring

Ring:-

  An algebraic system (R,+,.) consisting of a non-empty set R with two binary composition (to be denoted by addition and multiplication) is called a ring if following axiom are satisfied-
(R,+) is an abelian group.
1-    Closure axiom
2-    Associative law
3-    Identity element
4-    Inverse axiom
(R,.) is a semi group.
1-    Closure axiom
2-    Associative law
3-    Multiplication distributive over addition i.e.
a.(b+c)=a.b+a.c, a, b, cR
and   (b+c).a=b.a+c.a,  a, b, cR

         

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Linear Transformation Theorem-1

Statement:-

Let T be a linear transformation from avector space U into V over the field F.Then T is non-singular iff T is one-one.

Proof:-

Let T be a non-singular transformation from U into V.
Let α12U such that
                

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Vector Space Question-1

Question:- Express (1,2,3) as a linear combination of (1,1,1),(2,-1,1) and (1,-2,5) in V3(R).

Solution:- Let a1,a2,a3R such that
(1,2,3)=a1(1,1,1)+a2(2,-1,1)+a3(1,-2,5)……………………(a)
(1,2,3)=(a1,a1,a1)+(2a2,-a2,a2)+(a3,-2a3,5a3)

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Definition of Group

An algebraic system (G,o) where G be a non-empty set with o as defined binary operation is called a group if following axiom are satisfied-

1-    Closure Axiom:-

If a, bG  ⇨  aob∊G , ∀ a,b∊G
then G is said to be closed under the binary operation.

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Binary Operation & Algebric Structure

Binary operation or Binary composition on a set:-

Let G be a non-empty set then an operation ‘o’ on the non-empty set G is called binary operation.
          If aG, b aobG, a, bG
This property is called closure property and if this is satisfied then G is said to be closed under the binary composition ‘o’.

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Real & Quadratic Forms

Bilinear Form:-

Let U and V be two vector spaces over the same field F. A bilinear form on W=UV is a fraction f from W into F, which assigns to each element (α,β) in W a scalar f(α,β) in such a way that
f(aα1+bα2,β)= af(α1,β)+bf(α2,β)
&       f(α,aβ1+bβ2)=af(α,β1)+bf(α,β2)
Here f(α,β) is an element of F. It denotes the image of (α,β) under the function f. Thus a bilinear form on W is a function from W into F which is linear as a function of either of its arguments when the other is fixed.

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Linear Transformation (Question-1)

Question:-

Show that the mapping T:V2(R)V3(R) defined by T(a,b)=(a+b, a-b, b) is a linear transformation from V2(R) into V3(R).
Find the range, rank, null space and null(T) of T.

Solution:- Given that

T:V2(R)V3(R)
Such that T(a,b)=(a+b,a-b,b)

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Vector Space (Theorem-4)

Question:-

 Show that a field K can be regarded as a vector space over any subfield F of K.

Solution:- Let K be a field and F  be its subfield.

Since, K is a field,
Therefore,

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Union of two subspaces (Theorem)

Statement:-

The union of two subspace of a vector space is a subspace iff one each contained.

Proof:-

Let V be a vector space over the field F.Let W1 and W2 be its subspaces such that either

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Null Space, Rank, Nullity & Range

Range of a Linear Transformation:-

Let U and V be two vector spaces over the field F.Let T be a linear transformation from U into V then the of all vectors of V which are images of elements of U is called range of linear transformation. It is denoted by R(T).
Thus R(T)={T(α)V:αU}

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Annihilator Theorem-1

Theorem:-

Let V be a finite dimensional  vector space over the field F and let W be a subspace over the field F and let W be a subspace of V.Then W00=W.

Proof:-

We have
    W0={f∊V’ :f(α)=0  αW}………..(1)
And             W00={α∊V : f(α)=0  f∊W0}……..(2)

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Definition of annihilator

Annihilators:-

If V is a vector space over the field F and S is a subset of V,the annihilator of S is the set So of all linear functional f on V such that
f(α)=0   α∊S
Sometimes A(S) is also used to denote the annihilators of S.
Thus            S0={f∊V’: f(α)=0  α∊S}

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Annihilator Question-1

Question:-Let W1 and W2 be subspaces of a finite dimensional vector space V.
(a)Prove that (W1+W2)o=W10W20
(b)Prove that (W1W2)0=W10+W20.

Solution:-
(a)                       First we shall prove that
            W1W2(W1+W2)0.

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One-One, onto & Invertible linear transformation

One-one transformation:-

Let T be a transformation from a vector space U into V then T is said to be one-one transformation if
α12U and α1≠α2 T(α1)≠T(α2)
In other word
α12U and T(α1)=T(α2) α12

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Linear Transformation


Let U & V be two vector spaces over the same field F.A linear transformation from U into V is a function T:U→V, such that,
T(aα+bβ)=aT(α)+bT(β),for every a,bF and α,βU
This condition is also called linearity property.

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Theorem on linear sum

Statement:-

The linear sum of two subspaces of a vector space is also a subspace of same vector space.

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Linear Sum of two subspaces

Let V be a vector space over the field F the linear sum of two subspaces W1 and W2 of V written as (W1+W2) and is defined as W1+W2={α1+α2:α1єw1,α2єw2} which shows that each element 0f (W1+W2) is expressible as sum of an element of W1 and an element of W2.

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Linear Combination & Linear Span

Linear Combination Of Vectors:-

Let V be a vector space over the field F,then a vector αєV is said to be a linear combination of vectors α123,………………..αnєV.
If     α=a1α1+a2α2+a3α3+…………………………+anαn
where  a1,a2,a3,……………………………….anєF

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Invarience Theorem

Statement:-  Any two bases of a finite dimensional vector space have same number of elements.
OR
The number of elements in a basis of a finite dimensional vector space is unique.

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Intersection of two subspaces

Statement:-

The intersection of any two sub-spaces of a vector space is also a subspace of the same vector space.
Proof:-

Let V be a vector space over the field F and W1 and W2 be its subspaces.

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Inner Product Space

Let V be the vector space over the field F where F is either field of real numbers or field of complex number. An inner product space on V is a function from VχV into F which assigns to each ordered pairs of vectors α,β in V by a scalar (α,β) such that

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Existence Theorem

Statement:-There exists a basis for each finite dimensional vector space.

Proof:- 
Let V be vector space & let S={ α1,α2,……………..,αm } be a finite subset of V such that L(S)=V. If S is linearly independent then it is a basis of V.

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Vector Space (Theorem-3)

Statement:- The necessary and sufficient condition for a vector space V over the field F to be direct sum of its two subspaces W1 and W2 are that
1-V=W1+W2
2- W1 and W2 are disjoint i.e.  W1∩W2={0}

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Direct Sum of a vector space

Let V be a vector space over the field F then vector space V is said to be direct sum of its subspaces W1 and W2 written as   V=W1W2. If each element of V is uniquely expressible as sum of an element of W1 and an element of W2.
In this case W1 and W2 are called complementary subspaces.This definition can be extended for more than two subspaces.
i.e.       vector space V is said to be direct sum of its subspaces W1,W2,W3,………………………………….,Wn if every element αєV can be written in one and only one way
α=α123+…………………………..+αn
 where  α1єW12єW23єW3,…………………….αnєWn

Disjoint subspaces:-

Two subspaces W1 and W2 of a vector space V over the field F are said to be disjoint if their intersection(∩) with zero subspace.          i.e.  W1 andW2 are disjoint if W1∩W2={0}

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Basis, Dimension & Cosets of a vector Space

Basis of a vector space:-

A non-empty subset S of a vector space V(F) is said to be its basis if
1-S is linearly independent.
2-S generates V i.e. L(S)=V
i.e. each vector in V is expressible as a linear combination of element of S.

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Vector Space (Theorem-2)

Theorem:- If W is a subspace of an n-dimensional vector space over the field F then
dimW≤dimV

Proof:- 
Let W be a subspace of a finite dimensional vector space V(F).Let S={α12,…………………..αm} be a basis of V.

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Veactor Space (Theorem-1)

Statement-The necessary and sufficient condition for a non-empty subset W of vector space V is that
a,bєF, α,βєW aα+bβєW, a,bєF and α,βєW

Proof-                  Necessary condition-

Let W be a subspace of a vector space V over the field F.
               W is a vector space over the same field F. So  W is a closed under scalar multiplication.

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Definition of Vector Space


Let F be an orbitrary field then a non-empty set V is called a 
vector    space over the field F written as V(F) if following axioms are satisfied-
❶-There is defined an internal composition in V to be denoted additively such that (V,+) is an abelian group.
i.e.
1-Closure axiom:-
If α,β єV  then
α+βєV, ∀ α,βєBV

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