Y= N/D D≠0
Hence if
denominator is zero then real number can never be possible.
So 1/0, 2/0, 3/0,………..are practically
impossible.
i.e. 1/0=
undefined.
2- Under
the square root number can never be negative.
|
Y= √x
|
x≥0
3- Square
of any real number can never be negative.
Y= x2
y≥0 ⩝ x∈R
4-
Modulus of any real number can never be negative.
Y= |x|
y≥0 ⩝ x∈R
5- Sum of
two or more than two positive quantities always be positive.
Y= a+b+c ⩝ a, b, c≥0
6- Sum of square of two or more than two real
number will be zero if all the real numbers are individually zero i.e.
a2+b2+c2=
0 it is possible when a, b, c =0
Example:-
Find the value of (x-2)2+(y+3)2
=0 then find the value of x+y
Solution:-
(x-2)2+(y+3)2
=0
It is possible if & only if (x-2)2
=0 ⇨ x= 2
(y+3)2 =0 ⇨ y= -3
Then x+y = -3+2 = -1
By- Vinay Mishra
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1 comments:
Thank you vinay bhai
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